Given a nested list of integers, return the sum of all integers in the list weighted by their depth.
Each element is either an integer, or a list -- whose elements may also be integers or other lists.
Example 1:
Input: [[1,1],2,[1,1]]
Output: 10
Explanation: Four 1's at depth 2, one 2 at depth 1.
这道题算是LinkedIn的电话面试万年不变的一道题了,可以算是DFS,也可以算是BFS。思路差不多,对每一层的数字求和,按照深度加权,遇到list的时候把权重加一。
答出来之后一般会有个follow up,就是Nested List Weight Sum II
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
* // Constructor initializes an empty nested list.
* public NestedInteger();
*
* // Constructor initializes a single integer.
* public NestedInteger(int value);
*
* // @return true if this NestedInteger holds a single integer, rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds, if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // Set this NestedInteger to hold a single integer.
* public void setInteger(int value);
*
* // Set this NestedInteger to hold a nested list and adds a nested integer to it.
* public void add(NestedInteger ni);
*
* // @return the nested list that this NestedInteger holds, if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
class Solution {
public int depthSum(List<NestedInteger> nestedList) {
if(nestedList == null || nestedList.size() == 0)
return 0;
return depthSum(nestedList, 1);
}
public int depthSum(List<NestedInteger> nestedList, int factor) {
int res = 0;
for(NestedInteger n: nestedList) {
if(n.isInteger()) {
res += n.getInteger() * factor;
} else {
res += depthSum(n.getList(), factor + 1);
}
}
return res;
}
}